Python dictionary value is a list of problems encountered

A = [1,2,3,4,5,5,5,5,5,5,5]c = set (a) c = list (c) b = {}.fromkeys (a,[0,0,0,0,0]) for x in C:    b[x][0] = a.count (x) Print B

Guess what's going to happen?

I guess Python, in executing the program, takes A.count (x) as a constant to execute the loop, turning the first element of each list into a a.count (5)

But when you remove [0] representing the list

When you change b[x][0] = A.count (x) to B[x]=a.count (x), you get a different result:

Because of this dissected thing, two days of the program White ran, rely on.

If you want to achieve the effect of changing the value of the corresponding position of each list in turn, my solution is to set the dictionary default value to an empty string, using the concatenation output of the string ...

Python dictionary value is a list of problems encountered