Python Learning: Determining the number of alphanumeric spaces in a string

Enter a line of characters to count the number of letters, spaces, numbers, and other characters that contain English. Count the number of English alphabetic characters ' ' # -*- coding: utf-8 -*-import re# regular expression matching def ismathc (Src,pat):     pattern = re.compile (PAT)     result = re.match (PATTERN,SRC)     if result == None:         return 0    else:        return  1# determine the type of individual character: Def chargetype (character) the three elements in the:    #  array represent English letters, numbers, and spaces, respectively      type_num = [' [a-z]|[ A-z] ',  ' \d ',  ' \s ']    #  to determine whether the English alphabet     if ismathc ( Character, type_num[0])  == 1:        return 1     ELIF ISMATHC (character, type_num[1])  == 1:         return 2     elif ismathc (character, type_num[2])  == 1:         return 3    else:        return  4def getcharnum (str):     count = []    for i  in range (4):         count.append (0)      Print (Len (count))     for i in range (Len (str)):         if chargetype (Str[i]) ==1:             count[0]+=1        elif chargetype (Str[i]) ==2:             count[1]+=1         elif chargetype (Str[i]) ==3:             count[2]+=1        else:             count[3]+=1    return countstr= ' asc ss./ 124 ' Print ( Getcharnum (str))

Python Learning: Determining the number of alphanumeric spaces in a string