Python size is sorted based on the value of the dictionary

Num_dict = {' A ': +, ' B ': ten, ' C ': 8, ' d ': 0} #方法1 # new_dict = sorted (Num_dict.items (), Key=lambda x:x[1]) # Print (Dict (new_d ICT)) #方法2def new_dict (a_dict):    b_dict = {}  #用于存放排序后的字典    values = sorted (A_dict.values ())   #把16, 10,8,0 sorting    Print (values)  #打印出  [0, 8, ten,] #接下来要匹配key值 for    i in    values: for k,v in        num_ Dict.items (): #所有的数据项取出来            if v==i:                b_dict[k] = v  #添加数据项到b_dict字典里    print (b_dict) new_dict (num_ Dict

　　

Python size is sorted based on the value of the dictionary