Python uses the for loop to sort the elements in the list

This article introduces how to sort elements in a list using a for loop. This article introduces how to sort elements in a list using a for loop.

list = [13, 22, 6, 99, 11]for m in range(len(list)-1):    for n in range(m+1, len(list)):        if list[m]> list[n]:            temp = list[n]            list[n] = list[m]            list[m] = tempprint list

Result:

[6, 11, 13, 22, 99]

Analysis:

List = [13, 22, 6, 99, 11] for I in range (len (list)-1): for j in range (I + 1, len (list )): # print str (I) # print "init --" + str (j) print 'values of the list below this comparison '+ str (I), str (j) if list [I]> list [j]: # print I, j # print '-----' + str (list [I]) + str (list [j]) + '-------' T = list [j] list [j] = list [I] list [I] = T # print list [I], list [j] print '********* an internal loop **************** 'print list print listprint' +++ ++ the end of this internal cycle +++ ++ \ n \ n'

-- The circular process can be seen from the printed information --

Result:

The value of the list below this comparison is 0 1 [13, 22, 6, 99, 11] The value of the list under this comparison is 0 2 *, 22, 13, 99, 11] The value of the list under this comparison is 0 3 [6, 22, 13, 99, 11] The value of the list under this comparison is 0 4 [6, 22, 13, 99, 11] [6, 22, 13, 99, 11] ++ this internal cycle ends with ++ this comparison list under the standard value of 1 2 ********* internal, 13, 22, 99, 11] values under the list compared this time: 1 3 [6, 13, 22, 99, 11] In this comparison, the value of the list is 1 4 *, 11, 22, 99, 13] [6, 11, 22, 99, 13] ++ this internal cycle ends with ++ the list of marked values 2 3 [6, 11, 22, 99, 13] a loop inside the list marked as 2 4*6, 11, 13, 99, 22] [6, 11, 13, 99, 22] ++ this internal cycle ends with ++ this comparison list under the standard value of 3 4 ********* internal, 11, 13, 22, 99] [6, 11, 13, 22, 99] ++ the internal cycle ends.

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