Solve the error problem of JavaScript subtraction and tofixed

1     //to replace the original tofixed to solve the accuracy error problem2Number.prototype.mytofixed=function(s) {3       if(s = =NULL) {s = 0;}4       varValue = Math.pow (10,s);//Math.pow (x, y) returns the value of the Y-power of X, which is the value of the 10 len-squared5       //JavaScript's subtraction result will be error, using a custom method6       varReturnstr = Math.Round ( This. Mul (value)). div (value). toString ();7       //var returnstr= (parseint (This * value + 0.5)/value). toString ();8       varPointIndex = Returnstr.indexof ("."));9       if(PointIndex < 0 && s > 0) {//If there is no decimal point, add a decimal point and then 0TenReturnstr = Returnstr + "."; One          for(i = 0; i < s; i++){ AReturnstr = Returnstr + "0"; -         } -}Else { the         varWeishu = returnstr.length-1-PointIndex; -          for(i = 0; i < (S-weishu); i++) {//if there are decimal points, directly fill the missing 0 -Returnstr = Returnstr + "0"; -         } +       } -       returnReturnstr; +}

1     //multiplication function to get the exact multiplication result2     //Description: JavaScript multiplication results are error-evident when multiplying two floating-point numbers. This function returns a more accurate multiplication result. 3     //Call: Accmul (ARG1,ARG2)4     //return value: arg1 times the exact result of Arg25     functionAccmul (arg1, arg2) {6         varm = 0, S1 = arg1.tostring (), S2 =arg2.tostring ();7         Try{m + = S1.split (".") [1].length}Catch(e) {}8         Try{m + = S2.split (".") [1].length}Catch(e) {}9         returnNumber (S1.replace (".", "")) * Number (S2.replace (".", ""))/Math.pow (10, M)Ten     } One     //Usage: A     //Adding a Mul method to the number type makes it more convenient to call.  -Number.prototype.mul =function(ARG) { -         returnAccmul ( This, ARG); the}

1     //The division function, which is used to get accurate division results.2     //Description: The result of the division of JavaScript will be error, which will be obvious when dividing two floating-point numbers. This function returns a more accurate division result. 3     //Call: Accdiv (ARG1,ARG2)4     //return value: Arg1 divided by the exact result of Arg25     functionAccdiv (arg1, arg2) {6         varT1 = 0, t2 = 0, R1, R2;7         Try{T1 = arg1.tostring (). Split (".") [1].length}Catch(e) {}8         Try{t2 = arg2.tostring (). Split (".") [1].length}Catch(e) {}9          with(Math) {TenR1 = number (arg1.tostring (). Replace (".", "")) Oner2 = number (arg2.tostring (). Replace (".", "")) A             return(R1/R2) * POW (T2-t1); -         } -     } the     //Usage: -     //Adding a Div method to the number type makes it easier to call.  -Number.prototype.div =function(ARG) { -         returnAccdiv ( This, ARG); +}

1     //An addition function that is used to obtain accurate addition results2     //Note: The addition of JavaScript will have an error, and it will be more obvious when the two floating-point numbers are added. This function returns a more accurate addition result. 3     //Call: Accadd (ARG1,ARG2)4     //return value: Arg1 plus arg2 's exact result5     functionAccadd (arg1, arg2) {6         varR1, R2, M;7         Try{r1 = arg1.tostring (). Split (".") [1].length}Catch(e) {r1 = 0 }8         Try{r2 = arg2.tostring (). Split (".") [1].length}Catch(e) {r2 = 0 }9m = Math.pow (10, Math.max (R1, r2))Ten         return(ARG1 * m + arg2 * m)/m One     } A     //Usage: -     //Adding an Add method to the number type makes it more convenient to call.  -Number.prototype.add =function(ARG) { the         returnAccadd (ARG, This); -}

1     //subtraction function, which is used to get the exact subtraction result2     functionsubtr (arg1, arg2) {3         varR1, R2, M, N;4         Try{r1 = arg1.tostring (). Split (".") [1].length}Catch(e) {r1 = 0 }5         Try{r2 = arg2.tostring (). Split (".") [1].length}Catch(e) {r2 = 0 }6m = Math.pow (10, Math.max (R1, r2));7         //Last modify by Deeka8         //Dynamic Control accuracy length9n = (r1 >= r2)?r1:r2;Ten         return((ARG1 * M-ARG2 * m)/m). ToFixed (n);//we used tofixed here. One}

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Solve the error problem of JavaScript subtraction and tofixed