http://www.cnblogs.com/wupeiqi/p/5649402.html Five words take care of JavaScript scopes
from javascript = = Pyhon Scope Almost consistent __:one, "no block-level scope in JavaScript"There is a block-level scope in Java or C #, which is: curly braces are also a scope. There is no block-level scope in the Python \ JavaScript language.
# Scopes
# python no block level scope.
# java/c# may not take effect.
if1==1:
Name=' Alex '
Print(name) #effective. Alex
forIinchRange(Ten):
Name=I
Print(name) #9
# python takes a function as a scope.
deffunc():
name= ' Alex ' #name只在代码块中可以引用.
Func ()
Print(name) #cannot use output, error.
Second, the Python \javascript uses the function scope
when executing console.log (XO), its search order is
from inside to outside according to the scope chainthe priority of the search,if the inner layer does not look up gradually, until the throw exception is not found.
Iv. python \javascript has been created before the scope chain is executed
Python's scope is created before it is executed, and it is only necessary to follow the scope chain to find it later.
Scope chain
The scope is determined before execution. In the scope of the location, look up
# Example 1、
Name=' Alex '
defF1():
Print(name)
defF2():
name=' Eric '
F1 ()
F2 ()
#Execution Result:
#alex
Example 2 ,
#原理: But whatever function is used, such as F1 (), will be from F1 () your own function to look up. There's nothing to do with where you put the function.
Name=' Alex '
defF1(): #f1the scope of the location, looking up.
Print(name)
defF2():
name=' Eric ' #Inner Scope
returnF1
Ret=F2 ()
# print (ret)
RET ()
#Results
# <function F1 at 0x0000026c7d81df28>
# Alex
Sina interview questions:
# Example3 Advanced.
Li=[x+ - forXinchRange(Ten)ifX>6]
Print(LI)
#Execution Result:
# [107, 108, 109]
# Sina Interview questions:
# inLambdaas a list of elementsli=[Functions , functions, Functions, ]
Li1=[Lambda:X forXinchRange(4)]#lielements in a list, "functions, Functions, Functions",
Jit=[Lambda:1]
Li3=[x forXinchRange(Ten)]
Print(Lambda:9)
Print(li1[0])#a function name was generated and was not executed.
Ret=li1[0]()
Print(ret)
Print(li2[0]())
Print(LI3)
###########
Print([Lambda:9,][0]())#based on content--self-definedLambda ()executes the function.
#Execution Result:
# <function <listcomp>.<lambda> at 0x00000263d1ca80d0>
# 3
# 1
# [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
# 9
From for notes (Wiz)
Tip: Scope of Pyhon