C language Input Statements scanf and Fgets Linux

1. An example of testing using scanf:

#include "stdio.h"

#include "string.h"

int main ()

{

Char name[10];

scanf ("%s", name);

puts (name);

return 0;

}

Compile and invoke the following:

Can see the second time, due to the input string length, resulting in abort

2, the same example of a fgets:

#include "stdio.h"

#include "string.h"

int main ()

{

Char name[10];

Fgets (name, ten, stdin);

puts (name);

return 0;

}

Compile and invoke the following:

There is no case of abort like scanf, but a truncation of the string

3. Compare scanf and Fgets:

A) scanf does not restrict user input, resulting in the abort of the above test example

Fgets restricts the user's input, and then truncates the string, avoiding abort, but setting a buffer length value

b) scanf can be used such as scanf ("%d/%d", &x, &y) in such a way that the user only needs to enter 1/3 to get the values of x and Y respectively:

#include "stdio.h"

int main ()

{

int x;

int y;

scanf ("%d/%d", &x, &y);

printf ("x value:%d, y value:%d\n", x, y);

return 0;

}

But fgets, in any case, can only read one variable at a time, and it can only be a string (after all, it's str!). ), as in the following form, compilation is not a pass:

#include "stdio.h"

int main ()

{

int x;

Fgets (x, sizeof (x), stdin);

printf ("x Value:%d", x);

return 0;

}

c) spaces in the string

When scanf receives a string with%s, it stops when it encounters a space. If you want to enter multiple words, you need to call scanf () multiple times

Fgets () directly receives spaces in a string

4. Summary

Due to some of the differences mentioned in 3, be aware of the situation when using scanf () and fgets ().

Reproduced in: 19540153

C language Input Statements scanf and Fgets Linux