Today, when writing the framework, I want to use the Saemysql as a global variable after initializing it.
But later found that the global variables in PHP and Java or OC in the global variables are still a big difference.
The following is a note about the use of global in PHP.
1. There are situations where global variables are required, such as the following example:
<?php $name = "why";//define the variable name and initialize function echoname () { //try to reference the variable outside the function echo "MyName is". $ Name. " <br> "; } Echoname (); /* Why ask Hovertree.com */?>
The result of the above code is: "MyName is". Instead of the expected: "MyName is why". Because the function does not pass the value of the parameter $name, an attempt to reference an external variable does not succeed. Consider using global at this time.
2. Then change the code above to
<?php Global $name = "why";//Assign Function Echoname () with global Declaration () { //try to refer to the variable outside of the functions echo " MyName is ". $name." <br> "; } Echoname (); /* Why ask Hovertree.com */?>
The result is: Parse error:syntax error, unexpected ' = ', expecting ', ' or '; ' in http:\\xxxxxxx.com to line 2
That is, the code above has errors. The reason is that you cannot assign a value to a variable while declaring it with global.
3. Change the above code again:
<?php global $name; $name = "why";//separate global Declaration and assignment function echoname () { //try to reference a variable outside the function echo "MyName is". $name. " <br> "; } Echoname (); ? >
However, the result is still: "MyName is", because the use of global is not correct.
The correct usage for global is: "Introduce an external variable into a function, and if the variable is not passed through the parameter, it is introduced through global." "That is, when a function refers to an external variable, it can be declared within a function through global, so that the variable can be used in the function (equivalent to passing in as a parameter)."
4. Further changes are made to the above code:
<?php $name = "why";//define the variable name and initialize function echoname () { //through Global to declare $name, which is equivalent to passing parameters Global $name; echo "MyName is". $name. " <br> "; } Echoname (); /* Why ask Hovertree.com */?>
At this point we get the desired result: "MyName is why".
The code above shows that global is acting as a pass-through parameter, rather than making the scope of the variable global.
5. This is demonstrated by the following code:
<?php $name = "why";//declare variable $name and initialize function echoName1 () { //Use Global in function echoName1 () to declare $name global $name; echo "The first name is". $name. " <br> "; } /* Why ask Hovertree.com */function echoName2 () { //in function echoName2 () does not use global to declare $name echo "the second Name is ". $name." <br> "; } EchoName1 (); EchoName2 (); ? >
The result is:
The first name is why
The second name is
The above results show that in function echoName2 (), the $name variable is still unknown because it is not declared with global and is not passed in. It is also proved that global does not make the scope of the variable global.
In summary, the role of global is equivalent to passing parameters, variables declared outside the function, if you want to use within the function, you declare the variable with global, so it is equivalent to pass the variable in, you can reference the variable.
Of course, in addition to the above method, you can also use the global array $globals to solve the problem, where you need to use the external variables, the use of $globals[' var '. Cases:
<?php $name = "why";//define variable name and initialize function echoname () { //global array $globals to refer to external variable echo " MyName is ". $GLOBALS [' name ']." <br> "; } Echoname (); ? >
The results are as follows: MyName is.
Global variables: Difference and use between global and $globals