Javascript removeChild () is used to delete nodes and subnodes. javascript deletes nodes.

Javascript removeChild () is used to delete nodes and subnodes. javascript deletes nodes.

The following describes how to delete a node using Javascript removeChild (). The details are as follows:

In Javascript, only one method to delete a node is provided: removeChild ().

The removeChild () method is used to delete a subnode of the parent node.

Syntax:

Parent. removeChild (thisNode)

Parameter description:

 

Parameters	Description
ThisNode	Current node, that is, the node to be deleted
Parent	The parent node of the current node, that is, thisNode. parentNode.

For example, the statement for deleting a node with id = "demo" is:

var thisNode=document.getElementById("demo");thisNode.parentNode.removeNode(thisNode);

For example, delete a node:

<Div id = "demo"> <div id = "thisNode"> click Delete mE </div> <script type = "text/javascript"> document. getElementById ("thisNode "). onclick = function () {this. parentNode. removeChild (this) ;}</script>

Example:

 

As you can see, although Javascript only provides one method to delete nodes, It is enough.

Ps: JavaScript method for deleting subnodes

The HTML code is as follows:

<div id="f">  <div>a</div>  <div>b</div>  <div>c</div> </div> 

If you want to delete all the sub-nodes under Node f, You can naturally think of the following code:

var f = document.getElementById("f"); var childs = f.childNodes; for(var i = 0; i < childs.length; i++) {   alert(childs[i].nodeName);   f.removeChild(childs[i]); } 

After the program runs, we find that no child nodes can be completely deleted in either FireFox or IE.
As a node, so the results of deleting the node will be different.) This is because when you delete a subnode whose index is 0, the original index is natural.
When the index is set to 1, the index is changed to 0, and the variable I is changed to 1. When the program continues, it will delete the node whose index is 2 and is now 1, in this way, only half of the child nodes are deleted, and the result is also the same as that for in traversal. Delete all nodes normally
The Code is as follows:

for(var i = childs.length - 1; i >= 0; i--) {   alert(childs[i].nodeName);   f.removeChild(childs[i]); } 

We start to delete the index from the maximum value and adopt the descending method, so that the index will not change.

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