PHP to implement upload images saved to the database method. Share to everyone for your reference. The specific analysis is as follows:
PHP upload pictures, generally using the Move_uploaded_file method to save on the server. However, if a Web site has more than one server, you need to publish the image to all servers to be used normally (except for the image server)
If you save the picture data to the database, multiple servers can realize file sharing and save space.
First, the image file is binary data, so you need to save the binary data in the MySQL database.
The MySQL database provides a BLOB type for storing large amounts of data, and a BLOB is a binary object that can hold data of different sizes.
The BLOB type has the following four kinds, except the maximum amount of information stored is different, the other is the same. You can use different types depending on your needs.
Tinyblob Max 255B
Blob Max 65K
Mediumblob Max 16M
Longblob Max 4G
Datasheet photo, which is used to save picture data, is structured as follows:
Copy Code code as follows:
CREATE TABLE ' photo ' (
' ID ' int (a) unsigned not NULL auto_increment,
' type ' varchar not NULL,
' BinaryData ' Mediumblob not NULL,
PRIMARY KEY (' id ')
) Engine=myisam DEFAULT charset=latin1 auto_increment=1;
upload_image_todb.php:
Copy Code code as follows:
<?php
Connecting to a database
$conn = @mysql_connect ("localhost", "root", "") or Die (Mysql_error ());
@mysql_select_db (' demo ', $conn) or Die (Mysql_error ());
Judge Action
$action = Isset ($_request[' action ')? $_request[' action ']: ';
Upload pictures
if ($action = = ' Add ') {
$image = mysql_escape_string (file_get_contents ($_files[' photo '] [' tmp_name ']);
$type = $_files[' photo '] [' type '];
$sqlstr = "INSERT into photo (Type,binarydata) VALUES ('. $type." ', ' ". $image.") ";
@mysql_query ($sqlstr) or Die (Mysql_error ());
Header (' location:upload_image_todb.php ');
Exit ();
Show pictures
}elseif ($action = = ' Show ') {
$id = Isset ($_get[' id ')? Intval ($_get[' id '): 0;
$SQLSTR = "SELECT * from photo where id= $id";
$query = mysql_query ($sqlstr) or Die (Mysql_error ());
$thread = Mysql_fetch_assoc ($query);
if ($thread) {
Header (' Content-type: '. $thread [' type ']);
echo $thread [' binarydata '];
Exit ();
}
}else{
Display a picture list and upload a form
?>
<! DOCTYPE HTML PUBLIC "-//w3c//dtd HTML 4.01 transitional//en" "HTTP://WWW.W3.ORG/TR/HTML4/LOOSE.DTD" >
<meta http-equiv= "Content-type" content= "text/html; Charset=utf-8 ">
<title> upload image to db demo </title>
<body>
<form name= "Form1" method= "Post" action= "upload_image_todb.php" enctype= "Multipart/form-data" >
<p> Pictures: <input type= "file" name= "Photo" ></p>
<p><input type= "hidden" name= "action" value= "add" ><input type= "Submit" Name= "B1" value= "Submit" ></p >
</form>
<?php
$SQLSTR = "SELECT * from photo order by id DESC";
$query = mysql_query ($sqlstr) or Die (Mysql_error ());
$result = Array ();
while ($thread =mysql_fetch_assoc ($query)) {
$result [] = $thread;
}
foreach ($result as $val) {
Echo ' <p></p> ';
}
?>
</body>
<?php
}
?>
I hope this article will help you with your PHP program design.