Python print right triangle, equi triangle, diamond, square code, python equi-edge

Python print right triangle, equi triangle, diamond, square code, python equi-edge

Triangle

Isosceles right triangle 1 2.7

# Coding: utf-8rows = int (raw_input ('number of input columns: ') I = j = k = 1 # declare variable, I used to control the outer loop (number of rows in the graph ), j is used to control the number of spaces, k is used to control the number of * # isosceles right triangle 1 print "isosceles right triangle 1" for I in range (0, rows ): for k in range (0, rows-I): print "*", # note that "," must not be omitted, can play the role of not wrapping k + = 1 I + = 1 print "\ n"

Python: print right triangle

Coding = UTF-8

Method 1

i = 1while i <= 5:  j = 1  while j <=i:    print '*',    j+=1  print '\n'  i+=1

Method 2

for i in range(1, 6):  for j in range(1, i+1):    print "*",  print '\n'

# Print a solid equi-edge triangle

Print "print hollow equi triangle. Here, the if-else condition is determined to be solid." for I in range (0, rows + 1 ): # variable I control the number of rows for j in range (0, rows-I): # (1, rows-I) print "", j + = 1 for k in range (0, 2 * I-1): # (1, 2 * I) if k = 0 or k = 2 * I-2 or I = rows: if I = rows: if k % 2 = 0: # because the first number starts from 0, if an even number is printed *, the odd number prints the space print "*", else: print "", # note that "," must not be omitted. else: print "*", else: print "", k + = 1 print "\ n" I + = 1

# Print Diamond

Print "print hollow diamond. Here, the if-else condition is determined to be solid." for I in range (rows): # variable I control the number of rows for j in range (rows-I): # (1, rows-I) print "", j + = 1 for k in range (2 * I-1): # (1, 2 * I) if k = 0 or k = 2 * I-2: print "*", else: print "", k + = 1 print "\ n" I + = 1 # lower half of the diamond for I in range (rows): for j in range (I): # (1, rows-I) print "", j + = 1 for k in range (2 * (rows-I)-1): # (1, 2 * I) if k = 0 or k = 2 * (rows-I)-2: print "*", else: print "", k + = 1 print "\ n" I + = 1

# Solid square

Print "solid square" for I in range (0, rows): for k in range (0, rows): print "*", # note the following ",", it must not be omitted. It can be used for non-line breaks. k + = 1 I + = 1 print "\ n"

# Hollow Square

Print "Hollow Square" for I in range (0, rows): for k in range (0, rows): if I! = 0 and I! = Rows-1: if k = 0 or k = rows-1: # because the visual effect looks more like a square, spaces are added on both sides, increase the distance from print "*", # note that "," must not be omitted. else: print "can be used to avoid line breaks.", # There are three spaces in else: print "*", # Here * Space k + = 1 I + = 1 print "\ n" is added on both sides"

Knowledge POint Description:

Python, end = ''remarks

That is, do not wrap the line after printing. Use "," In Python2.7
The following is an example of 2.7:
Def test ():
Print 'hello ',
Print 'World'

In python3, 'end = 'means no line break.

Python print flip triangle

1. Write Functions in the above mode.

Prompt the user to enter n and call displayPattern (n) to display this mode.

Def displayPattern (n): dict ={} for I in range (0, int (n): ''' int (I) + 2: Left closed and right open eg: n = 3, I = 0, print [1] I = 1, print [1, 2]... str (j) [:-1]: Reverse type of a single string. For example: 12 ==> 21, add to the dictionary ''' dict [I] = [str (j) [:-1] for j in range (1, int (I) + 2)] listNum = [] # print (dict) for key, value in dict. items (): ''' {0: ['1'], 1: ['1', '2'], 2: ['1', '2 ', '3'], 3: ['1', '2', '3', '4'], cyclically retrieve the value in the dictionary (corresponding list) to remove [], (replace comma with space and single quotation marks with null) ==> add to list ''' value = str (value ). strip ('[]'). replace (',', '\ t '). replace ("'", '') listNum. append (value) # print (value) for k in range (0, int (n): ''' "\ t" * % s: space * string form % (int (n)-int (k)-1) [:-1]: %: Format mark int (n) -int (k)-1: how many spaces are required? ''' listNum [k] = (listNum [k] + (eval ('"\ t" * % s' % (int (n)-int (k) -1) [:-1] print (listNum [k]) # print (dict) # print (listNum) num = int (input ("enter a number:") # Call the displayPattern (num) function)