For the cout computing sequence, the order is calculated from right to left.

1 # Include <iostream>
 2   Using   Namespace STD;
 3  
 4   Int Main ()
 5 {
 6       Const   Int A [] = { 10 , 20 ,30 };
 7       Const   Int * P =;
 8 Cout < "  * P:  " <* P <Endl;
 9 Cout < "  * P:  " <* P < "  \ T * P ++: " <* P ++ < "  \ T * P  " <* P <Endl;
 10       Return   0 ;
 11 }
 12  
 13   /*  Output:
  14   * P: 10
  15  * P: 20 * P ++: 10 * P: 10 

 
*/
 

From the above example, we can see that the cout calculation order is from right to left. First, we can obtain the first element 10 by referencing * P, then, in the second output statement, from the right to the left, first obtain 10 for the solution reference, and then calculate * P ++. For the calculation of * P ++, see: for example, I = 3; cout <I ++ <Endl; Also outputs 3 because I is output first, and then the I value is changed. Output * P is 10 first, but after this formula is calculated, * p becomes 20 for the second element, that is, the first * P is 20, and the output is 10.