Four-color three-elimination game algorithm

Four-color three-elimination game algorithm

The following is a python-written four-color three-elimination game algorithm, it is easy to change into more colors and ranks. The basic idea is that 3 of the same diamonds together can be eliminated. Nonsense not to say, on the code:

#!/usr/bin/python#-*-Coding:utf-8-*-#====================================================================== Import OS import sysimport getoptimport timeimport random#========================================================== ============# Color Output#def perror (s): print ' \033[31m[error]%s\033[31;m '% (s) def pinfo (s): print ' \033[32m[inf O]%s\033[32;m '% (s) def Pwarn (s): print ' \033[33m[warn]%s\033[33;m '% (s) #------------------------------------------- ---------------def Red (): print ' \033[31ma\033[31;m ', Def Yellow (): print ' \033[33mb\033[33;m ', Def Blue (): print ' \033[34mc\033[34;m ', Def Green (): print ' \033[32md\033[32;m ', Def one (): print ' \033[31m1\033[31;m ', Def Zero (): PRI NT ' O ', Def pout (C): If c== ' A ': Red () elif c== ' B ': yellow () elif c== ' C ': Blue () elif C = = ' D ': Green () Else:zero () #==========================================================# 4 colors and 3 cr Ash for 5x7 Diamonds tablecrash3_cols = 7CRash3_rows = 5crash3_colors = [' O ', ' A ', ' B ', ' C ', ' D ']crash3_diamonds_table = [[0,0,0,0,0,0,0], [0,0,0,0,0,0,0], [0    , 0,0,0,0,0,0], [0,0,0,0,0,0,0], [0,0,0,0,0,0,0],]crash3_diamonds_result = [[0,0,0,0,0,0,0], [0,0,0,0,0,0,0], [0,0,0,0,0,0,0], [0,0,0,0,0,0,0], [0,0,0,0,0,0,0],]def crash3_print_colors (table): For row in range (0, crash3_ ROWS, 1): For Col in range (0, Crash3_cols, 1): color = Table[row][col] Pout (crash3_colors[col or]) print ' Def crash3_print_values (table): For row in range (0, crash3_rows, 1): For Col in range (0, CRA Sh3_cols, 1): v = table[row][col] if v = = 1:one () else:ze RO () print ' Def crash3_reset_value (table, V): For row in range (0, crash3_rows, 1): For Col in range (0, C Rash3_cols, 1): table[row][col] = vdef crash3_init_table (table): print ("\ n----------------------\ncrash3_ini t_table:\n----------------------") color = Random.randint (1, 4) for row in range (0, crash3_rows, 1): For Col in range (0, Crash3_cols, 1): color = Random.randint (1, 4) table[row][col] = colordef crash3_on_cell (table, result, row, col) : If col < crash3_cols-2: (a,b,c) = (Table[row][col], table[row][col+1], table[row][col+2]) if a==b            and B==c:result[row][col] = 0;            Result[row][col+1] = 0;    RESULT[ROW][COL+2] = 0; If row < crash3_rows-2: (a,b,c) = (Table[row][col], Table[row+1][col], Table[row+2][col]) if A==b and b            ==c:result[row][col] = 0;            Result[row+1][col] = 0; Result[row+2][col] = 0;def crash3_on_trigger (table, result): print ("\ n----------------------\ncrash3_on_trigger:\ N----------------------") for row in range (0, crash3_rows, 1): For Col in range (0, Crash3_cols, 1): C Rash3_on_cell (table, result, row, col) #==========================================================# Main () entryif __name__ = = "__main__": pinfo ("Crash linked 3 Diamonds.\ncopyright by cheungmin    E, all rights reserved! ") Crash3_init_table (crash3_diamonds_table) crash3_print_colors (crash3_diamonds_table) Crash3_reset_value (CRASH3_ Diamonds_result, 1) crash3_on_trigger (crash3_diamonds_table, Crash3_diamonds_result) crash3_print_values (CRASH3_     Diamonds_result)

Run results, O for elimination, 1 for no elimination:

In practical use, it is easy to change to another language.

Four-color three-elimination game algorithm