I saw this shell interview question before: get a list of 51CTO blogs sorted in reverse chronological order http://oldboy.blog.51cto.com/2561410/1860985
Since I've been learning python for a while, think about using Python to solve problems.
Idea: Through the requests module to obtain the Web page source code, through the split () function to get the total number of pages, stitching the string to get all the URL of the blog address. Similarly, the source code of all the pages is obtained through requests and the key information is obtained through regular matching, thus stitching out the HTML page.
#coding: Utf-8import requestsimport re,sysreload (SYS) sys.setdefaultencoding (' Utf-8 ') # get page def page (): url = ' http://oldboy.blog.51cto.com/all/2561410 ' content = requests.get (URL). Content msg = re.findall (R ' <center> (. *) </center> ', content) [0] return msg.split ('/') [ -1].split () [0 ]# get key information and Stitch Htmldef oldboy (): uri = ' http://oldboy.blog.51cto.com/ all/2561410/page/' num = page () res = [] for i in range (num): &NBSP;URL&NBSP;=&NBSP;URI&NBSP;+&NBSP;STR (int (i) +1) content = Requests.get (URL). Content res += re.findall (R ' <a href= "(/\d+/\d+)" > (. *) </a> ', content) &NBSP;&NBSp; # res format [('/2561410/1867160 ', ' 2017\XD7\XEE\XD0\XC2\XC6\XF3\XD2\XB5SHELL\XC3\XE6\XCA\XD4\XCC \xe2\xbc\xb0\xc6\xf3\xd2\xb5\xd4\xcb\xce\xac\xca\xb5\xd5\xbd\xb9\xb230\xb5\xc0\xb0\xb8\xc0\xfd '),...] html = ' for i in res: msg = i[1].decode (' GBK ') href = ' HTTP// Oldboy.blog.51cto.com ' +i[0] html += ' <p><br></p><p>{0 }</p><p><a href= ' {1} ' target= ' _blank ' >{1}</a></p> '. Format (MSG,HREF) # html format "<p><br></p><p> 2017 the latest enterprise Shell face test and enterprise operation and maintenance 30 cases </p><p><a href= ' http://oldboy.blog.51cto.com/2561410/1867160 ' target= ' _blank ' >http://oldboy.blog.51cto.com/2561410/1867160</a></p>, ... " with open (' oldboy_blog.html ', ' W ') as f: f.write (HTML) if __name__== ' __main__ ': oldboy ()
HTML page
650) this.width=650; "src=" Http://s5.51cto.com/wyfs02/M02/89/C2/wKioL1gcAVmTchDtAAAyUb0_Jo0894.png "title=" Qq20161104113227.png "alt=" Wkiol1gcavmtchdtaaayub0_jo0894.png "/>
Get a 51CTO blog list in reverse chronological order using Python