Get the parameters in the URL

JS gets the parameters after the URL

Law one-Regular expression:

function getQueryString(name) {         var reg = new RegExp("(^|&)" + name + "=([^&]*)(&|$)", "i");         var r = window.location.search.substr(1).match(reg);         if (r != null) return unescape(r[2]);         return null;     

Method Two-split string:

function GetRequest() {     var url = location.search; //获取url中"?"符后的字串     var theRequest = new Object();     if (url.indexOf("?") != -1) {        var str = url.substr(1);        strs = str.split("&");        for(var i = 0; i < strs.length; i ++) {           theRequest[strs[i].split("=")[0]]=unescape(strs[i].split("=")[1]);        }     }     return theRequest;  }  

Method Three-Gets the specified parameter:

 /**  * 获取指定的URL参数值  * URL:http://www.quwan.com/index?name=tyler  * 参数：paramName URL参数  * 调用方法:getParam("name")  * 返回值:tyler  */ function getParam(paramName) {     paramValue = "", isFound = !1;     if (this.location.search.indexOf("?") == 0 && this.location.search.indexOf("=") > 1) {         arrSource = unescape(this.location.search).substring(1, this.location.search.length).split("&"), i = 0;         while (i < arrSource.length && !isFound) arrSource[i].indexOf("=") > 0 && arrSource[i].split("=")[0].toLowerCase() == paramName.toLowerCase() && (paramValue = arrSource[i].split("=")[1], isFound = !0), i++     }     

Get the parameters in the URL