Given two array of strings, find out the different elements

Title Description: Given s = {"A", "B", "C", "D", "F", "E", "AB"}; S2 = {"A", "AB"}; Find out that the remaining elements in S2 are not included in S. Can be considered as the result of S-S2.

Idea: Using HashMap, the elements in s are stored in HashMap, and the value in <K,V> is assigned a value of 1, and then the elements in the S2 are traversed, if there is value+1 in S1, then the element of value 1 is found.

1 ImportJava.util.*;2 ImportJava.util.Map.Entry;3  Public classStringminute {4      Public Static voidMain (string[] args) {5String[] s = {"A", "B", "C", "D", "F", "E", "AB"};6string[] S2 = {"A", "AB"};7         8map<string, integer> map =NewHashmap<>();9          for(inti=0; i<s.length; i++){TenMap.put (S[i], 1); One         } A          for(inti=0; i<s2.length; i++){ -             if(Map.containskey (S2[i])) { -                 intCount =Map.get (S2[i]); thecount++; - Map.put (S2[i], count); -             } -         } +Iterator iter =Map.entryset (). iterator (); -          while(Iter.hasnext ()) { +map.entry<string, integer> Entry = (entry<string, integer>) Iter.next (); A             if(Entry.getvalue () = = 1){ at System.out.println (Entry.getkey ()); -             }  -         } -     } -}

Given two array of strings, find out the different elements