# Greedy algorithm--coin problem

Source: Internet
Author: User

There are 1 yuan, 5 yuan, 10 yuan, 50 yuan, 100 yuan, 500 yuan coins each c1,c5,c10,c50,c100,c500 pieces. Now it's time to use these coins to pay a, at least how many coins you need.

```#include <iostream>
using namespace std;
int v[6] = {1, 5, 10, 50, 100, 500};//coin face
int c[6] = {3, 2, 1, 3, 0, 2};//coin corresponds to the number of
int count = 0;
int A;
Calculate the minimum required number of coins
void Solve ()
{for
(int i = 5; 0 <= i; i)
{
int t = min (A/v[i], c[i]);
A-=  v[i] * t;
Count + = t;
}
if (A = = 0)
cout << count;
else
cout << "There is no way!";
}
int main ()
{
cin >> A;
Solve ();
return 0;
}
```

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