Hack-PHP information security (intrusion acquisition $ flag) question [Q1]

Address: 202.120.7.small: 8888collision. php is participating in the ISG competition. Well, it is hopeless to win the prize. But as a PHPer, I feel that this code is okay... Please try again. How to get $ flag...

URL: http: // 202.120.7.20.: 8888/collision. php

I am participating in the ISG competition. Anyway, I have no hope to win the prize. But as a PHPer, I feel that this code is okay...
Please try again.
How to get $ flag...

Reply content:

URL: http: // 202.120.7.20.: 8888/collision. php

I am participating in the ISG competition. Anyway, I have no hope to win the prize. But as a PHPer, I feel that this code is okay...
Please try again.
How to get $ flag...

Http: // 202.120.7.20.: 8888/collision. php? Md5 = mcfog_42r6i8

To put it simply,=This is definitely wrong when it appears in php code.

The problem here is that'0e1 '= '0e2'

That is to say, you need to find the string with md5 as '0e number' and write a loop to find it.

Probability is(1/16) ^ 2 * (10/16) ^ 30You can find 7 digits for 0.5 billion digits.

Try this.
Http: // 202.120.7.20.: 8888/collision. php? Md5 = QNKCDZO
Output result:
ISG {not_OnlY_mD5_c0llisi0N_bUt_aLs0_proBl3m}