Hangzhou Electric 2988--dark Roads

Dark roads

Time limit:2000/1000 MS (java/others) Memory limit:32768/32768 K (java/others)
Total submission (s): 798 Accepted Submission (s): 329

Problem descriptioneconomic times these days is tough, even in Byteland. To reduce the operating costs, the Government of Byteland have decided to optimize the road lighting. Till now every road is illuminated all night long, which costs 1 Bytelandian Dollar per meter and day. To save money, they decided to no longer illuminate every road, but to switch off the road lighting of some streets. To make sure this inhabitants of Byteland still feel safe, they want to optimize the lighting in such a-a, that afte R darkening some streets at night, there'll still be at least one illuminated path from every junction in Byteland to Ev ery other junction.

What's the maximum daily amount of money the government of Byteland can save, without making their inhabitants feel Unsaf E?

Inputthe input file contains several test cases. Each test case is starts with a numbers m and N, the number of junctions in Byteland and the number of roads in Byteland, R Espectively. Input is terminated by m=n=0. Otherwise, 1≤m≤200000 and m-1≤n≤200000. Then follow n integers triples x, y, z specifying that there'll be a bidirectional road between x and y with length Z met ERs (0≤x, y < M and x≠y). The graph specified by all test case is connected. The total length of any roads in each test case is less than 231.

Outputfor each test case, print one line containing the maximum daily amount the government can save.

Sample Input7 11 0 1 7 0 3 51 2 8 1 3 9 1 4 7 2 4 53 4 15 3 5 64 5 8 4 6 9 5 6 11 0 0

Sample Output51

source2009/2010 ULM Local Contest

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1#include <cmath>2#include <cstdio>3#include <cstring>4#include <iostream>5#include <algorithm>6 using namespacestd;7 intfather[200200];8 intN, M;9 structrodeTen { One     intx, Y, W; A} num[200200], shu[200200]; -  - BOOLCMP (Rode X, rode y) the { -     returnX.W >Y.W; - } -  + BOOLCPM (Rode X, rode y) - { +     returnX.W <Y.W; A } at  - voidInit () - { -      for(inti =0; I < n; i++) -Father[i] =i; - } in  - intFindinta) to { +     if(A = =Father[a]) -         returnA; the     Else *         returnFather[a] =find (Father[a]); $ }Panax Notoginseng  - BOOLMercyintAintb) the { +     intQ =find (a); A     intp =find (b); the     if(Q! =p) +     { -FATHER[Q] =p; $         return true; $     } -     Else -         return false; the } - Wuyi intMain () the { -      while(~SCANF ("%d%d", &n, &m), n+m) Wu     { -Init ();intsum =0; About          for(inti =0; I < m; i++) $         { -scanf" %d%d%d", &num[i].x, &AMP;NUM[I].Y, &NUM[I].W); -shu[i].x = num[i].x; Shu[i].y = NUM[I].Y; SHU[I].W =NUM[I].W; -Sum + =NUM[I].W; A         } +         /*int sum = 0; the sort (num, num + M, CMP); - for (int i = 0; i < m; i++) $         { the if (Mercy (num[i].x, num[i].y)) the sum + = NUM[I].W; the         }*/ the         intTotal =0; -Sort (Shu, Shu +m, CPM); in          for(inti =0; I < m; i++) the         { the             if(Mercy (shu[i].x, shu[i].y)) AboutTotal + =SHU[I].W; the         }  theprintf"%d\n", ABS (Sum-Total )); the     } +     return 0; -}

Hangzhou Electric 2988--dark Roads