HDU 1050 Moving Tables (Greedy), hdutables
Moving Tables
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission (s): 20302 Accepted Submission (s): 6889
Problem DescriptionThe famous ACM (Advanced Computer Maker) Company has rented a floor of a building whose shape is in the following figure.
The floor has 200 rooms each on the north side and south side along the corridor. recently the Company made a plan to reform its system. the reform provided des moving a lot of tables between rooms. because the corridor is narrow and all the tables are big, only one table can pass through the corridor. some plan is needed to make the moving efficient. the manager figured out the following plan: Moving a table from a room to another room can be done within 10 minutes. when moving a table from room I to room j, the part of the corridor between the front of room I and the front of room j is used. so, during each 10 minutes, several moving between two rooms not sharing the same part of the corridor will be done simultaneously. to make it clear the manager has strated the possible cases and impossible cases of simultaneous moving.
For each room, at most one table will be either moved in or moved out. now, the manager seeks out a method to minimize the time to move all the tables. your job is to write a program to solve the manager's problem.
InputThe input consists of T test cases. the number of test cases) (T is given in the first line of the input. each test case begins with a line containing an integer N, 1 <= N <= 200, that represents the number of tables to move. each of the following N lines contains two positive integers s and t, representing that a table is to move from room number s to room number t (each room number appears at most once in the N lines ). from the N + 3-rd line, the remaining test cases are listed in the same manner as abve.
OutputThe output shoshould contain the minimum time in minutes to complete the moving, one per line.
Sample Input
3 4 10 20 30 40 50 60 70 80 2 1 3 2 200 3 10 100 20 80 30 50
Sample Output
102030
SourceAsia 2001, Taejon (South Korea)
Solution: greedy. Considering the optimal solution each time, the two rooms on the opposite side share their corresponding regions. A conflict occurs each time they are staggered, which means they cannot carry the same operation, considering the staggered areas of multiple transfers, the maximum number of staggered operations represents the minimum number of moves.
AC code:
# Include <iostream> # include <cstdio> # include <string> # include <cstring> # include <algorithm> using namespace std; int room [205]; int main () {// freopen ("in.txt", "r", stdin); int t, n, x, y; scanf ("% d", & t ); while (t --) {memset (room, 0, sizeof (room); scanf ("% d", & n); for (int I = 0; I <n; I ++) {scanf ("% d", & x, & y); if (x> y) swap (x, y ); // prevent the starting room from being greater than the ending room for (int I = (x + 1)/2; I <= (y + 1)/2; I ++) {room [I] ++; // increase in the number of disconnections in the corresponding area} int ans = 0; for (int I = 1; I <= 201; I ++) {if (ans <room [I]) ans = room [I];} printf ("% d \ n", ans * 10);} return 0 ;}