How do I insert the current time into a table?

The following code is inserted into the current table to insert the data with a time column type of timestamp I just want to insert the data into the table. What should I do with the code below? Just change it here, all right?

$stmt=$pdo->prepare("insert into blog(tid,title,content,name)values(:tid,:title,:content,:name)");$stmt->execute($_POST);

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The following code is inserted into the current table to insert the data with a time column type of timestamp I just want to insert the data into the table. What should I do with the code below? Just change it here, all right?

$stmt=$pdo->prepare("insert into blog(tid,title,content,name)values(:tid,:title,:content,:name)");$stmt->execute($_POST);

The time zone is set with Date.timezone this option in php.ini, but it is turned off by default
The PHP explanation shows the time "Greenwich Mean Time", which differs from our local time by 8 hours---------time zone must be correct

The now () function returns the current datetime with ' Yyyy-mm-dd HH:MM:SS ' and can be stored directly in the DateTime field.

Curdate () returns today's date in the format ' Yyyy-mm-dd ', which can be stored directly in the Date field.

Curtime () returns the current time in the format ' HH:MM:SS ', which can be stored directly in the Date field.

1. MySQL statementinsert into xxxx (addDateTime) values (now())
   2.mysql statement ' INSERT INTO now ' (ID, Nowtime) VALUES (' 1 ', now ())

Remember to manually fix the slack, as follows:
$timeoffset = 8;
Echo gmdate ("y-m-d h:i:s", mktime () + $timeoffset * 3600). "
";
Echo gmdate ("y-m-d h:i:s", Time () + $timeoffset * 3600). "
";
echo Date ("Y-m-d h:i:s", mktime () + $timeoffset * 3600). "
";
echo Date ("Y-m-d h:i:s", Time () + $timeoffset * 3600). "
";
Both output the following format: 2007-11-24 17:41:58
$t = Gmdate ("y-m-d h:i:s", mktime () + 8 * 3600)
$sql = "INSERT into xxxx (adddatetime) VALUES ($t)"

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