How does a regular match the first </p> and the last </p>

How the regular matches the first one.

And the last one

such as the article below

1111111

2222222

33333333

4444444

55555555

66666666

7777777

Match out

1111111

In the

And the last paragraph

7777777

Of

How do you get it?

Share to:

------Solution--------------------
Preg_match_all ('/^

.+<\/p>
------Solution--------------------

. +<\/p>$/u ', $s, $m);
------Solution--------------------

$s =<<< TXT
1111111

2222222

33333333

4444444

55555555

66666666

7777777

TXT;
echo Preg_replace (' # (
)(.+)(
) #s ', ' $1aaa$2$3bbb ', $s);

1111111

AAA

2222222

33333333

4444444

55555555

66666666

7777777

BBB


References:

Quote: References:

Quote: References:

If you just want to match

, you can use the regular.
PHP5, no one should use PHP4 now ...

$str = '
1111111

2222222

33333333

4444444

55555555

66666666

7777777
';
$fp = Stripos ($str, '
');
$first = substr ($str, $FP, 4);
$ep = Stripos ($str, '
');
$end = substr ($str, $EP, 4);

Wrongly written, $ep = Strripos ($str, '

');
The upstairs brothers and I want to be the same.

Actually, I want the first paragraph. Append some text, and the last paragraph to append some text

------Solution--------------------
reference:

Quote: reference:
Quote: reference:

If you just want to match

If you want, you can use the regular.
PHP5, no one should use PHP4 now ...

 
 $str = ' 
 1111111 
 
 
 2222222 
 
 
 33333333 
 
 
 4444444 
 
 
 55555555 
 
 
 66666666 
 
 
 7777777 
 '; 
 $fp = Stripos ($str, ' 
 
 '); 
 $first = substr ($str, $FP, 4); 
 $ep = Stripos ($str, ' 
 
 '); 
 $end = substr ($str, $EP, 4);
    
 

was incorrectly written, $ep = Strripos ($str, '

'); The
upstairs brothers and I think the same.

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