How JavaScript jumps out of multiple cycle break, continue_javascript skills

Let's talk about the difference between break and continue.

Excerpt from JavaScript advanced programming

for (Var i=0;i<10;i++) {
  if (i>5) {break
  ;
  }
}
Console.log (i);  ---6

• When i=5 and 10 are executed to the break and exit the loop

 for (Var i=1;i<10;i++) {
  if (i>5) {
  continue
  }
  num++;
}
Console.log (num);  ---4

var num=0;
for (Var i=1;i<10;i++) {
  if (i%5==0) {
  continue
  }
  num++;
}
Console.log (num); ---8

• When i=5 or i=10, follow the value of I, continue with the For loop, and exit the loop

When multiple loops are executed

The condition of the break

Outer: For
(var i=0;i<10;i++) {
 Inter: for
  (var j=0;j<10;j++) {
    if (i>5)
    { Console.log (i); ----6 Break 
     outer}
    } 
 

This is the break to the outermost loop inside

Outer: For
(var i=0;i<10;i++) {
 Inter: for
  (var j=0;j<10;j++) {
    if (i>5) {
    Console.log (i) ; ----6,7,8,9 break 
     inter;
    }
  } 
 

This is a break to the inner surface of the time, although not jump out for the moment, but 4 times after execution, or jumped out

The situation of continue

var num=0;
Outer: For
(var i=0;i<10;i++) {
 Inter: for
  (var j=0;j<10;j++) {
    if (i>5)
    { Console.log (i); ----6,7,8,9 
     continue outer;
    }
    num++  
  } 
 }
 Console.log (num);     ---60

Whenever I is greater than or equal to 5 will pop up to continue the cycle, so, will be less than 40 times.

var num=0;
Outer: For
(var i=0;i<10;i++) {
 Inter: for
  (var j=0;j<10;j++) {
    if (i>5)
    { Console.log (i); ----6,7,8,9 
     continue inter;
    }
    num++  
  } 
 }
 Console.log (num);     ---60

The same principle, the loop will continue to execute, but only less 40 times, because the limit is always the value of I, I is less than or equal to 5 will not be set up.

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