How Python Calculates the time difference

This example describes how Python calculates the time difference. Share to everyone for your reference. The specific analysis is as follows:

1. Questions:

Given your two dates, how do you calculate between these two dates in a few days, weeks, months, years?

2. Solution:

The standard module datetime and third-party package dateutil (especially the Dateutil Rrule.count method) can help you solve this problem very quickly and easily.

From dateutil import rruleimport datetimedef weeks_between (start_date, end_date):  weeks = Rrule.rrule (rrule. WEEKLY, Dtstart=start_date, until=end_date)  return Weeks.count ()

The Rrule method allows you to set the scale calculation based on the date (DAILY), Week (WEEKLY), year (yearly). Here's a piece of code to test:

If _ _name_ _== ' _ _main_ _ ':  starts = [Datetime.date (2005,, Datetime.date)]  end = 2005 Te (2005, MB) for  s in starts: Days    = Rrule.rrule (rrule. DAILY, Dtstart=s, Until=end). Count ()    print "%d days shows as%d weeks" percent (days, weeks_between (s, end))

This will output the result:

7 days shows as 1 weeks
8 days shows as 2 weeks

The Rrule calculation is calculated as an integer, and it does not return a result of 0.5 weeks, so 8 days will be counted as two weeks.

Of course you don't have to define a size, just a return Rrule.rrule (Rrule). WEEKLY, Dtstart=start_date, Until=end_date). Count () to get the results.

Hopefully this article will help you with Python programming.

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