How Python executes a specified function at timed intervals

The example in this article describes how Python executes the specified function at timed intervals. Share to everyone for your reference. The implementation method is as follows:

# time a function using Time.time () and the A @ function decorator# tested with PYTHON24 vegaseat 21aug2005import Timede F print_timing (func): Def wrapper (*arg): T1 = time.time () res = func (*arg) t2 = time.time () print '%s took%0 .3f ms '% (Func.func_name, (T2-T1) *1000.0) return res return wrapper# declare the @ decorator just before the function , invokes Print_timing () @print_timingdef getprimelist (n): "" "returns a list of prime numbers from 2 to < n using a Si   Eve algorithm "" "If n < 2:return [] if n = = 2:return [2] # do-odd numbers starting at 3 S = Range (3, n+1, 2)    # n**0.5 May is slightly faster than MATH.SQRT (n) mroot = n * * 0.5 half = Len (s) i = 0 m = 3 while M <= mroot:   If s[i]: j = (m*m-3)//2 s[j] = 0 while J < half:s[j] = 0 J + = m i = i+1 m = 2*i+3 return [2]+[x for x in S if x]if __name__ = = "__main__": print "prime numbers from 2 to <10,000,000 using a sieve al Gorithm "primelist = geTprimelist (10000000) time.sleep (2.5) "" "My output-->prime numbers from 2 to <10,000,000 using a sieve ALGORITHMGETP Rimelist took 4750.000 ms "" "

Hopefully this article will help you with Python programming.

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