How to achieve the number of online statistics in PHP

Source: Internet
Author: User
Tags chmod flock php programming

This article is an example of how to achieve the number of online statistics website in PHP. Share to everyone for your reference. The implementation methods are as follows:

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1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 The <?php function getipaddress () {//Get the current user's IP address if (getenv (' Http_ Client_ip ')) {$ip = getenv (' http_client_ip ');} elseif (getenv (' http_x_forwarded_for ')) {$ip = getenv (' http_x_forwarded _for '); } elseif (getenv (' remote_addr ')) {$ip = getenv (' remote_addr ');} else {$ip = $_server[' remoe_addr '];} return $IP; function Writeover ($filename, $data, $method = ' W ', $chmod = 0) {$handle = fopen ($filename, $method);!handle && di E ("File open failed"); Flock ($handle, LOCK_EX); Fwrite ($handle, $data); Flock ($handle, lock_un); Fclose ($handle); $chmod && @chmod ($filename, 0777); function Count_online_num ($time, $ip) {$fileCount = './count.txt '; $count = 0; $gap = 900;//15 minutes does not refresh the page on if (!file_exIsts ($fileCount)) {$str = $time. "T". $ip. "RN"; Writeover ($fileCount, $str, ' W ', 1); $count = 1; else {$arr = file ($fileCount); $flag = 0; foreach ($arr as $key => $val) {$val = Trim ($val); if ($val!= "") {List $ When, $seti) = Explode ("T", $val); if ($seti = = $ip) {$arr [$key] = $time. "T". $seti; $flag = 1; else {$currentTime = time (); if ($currentTime-$when > 900) {unset ($arr [$key]);} else{$arr [$key]= $val;}} } if ($flag = = 0) {Array_push ($arr, $time. "T". $IP); $count = count ($arr); $str = Implode ("rn", $arr); $str. = "RN"; Writeover ($fileCount, $str, ' W ', 0); Unset ($arr); return $count; $time = time (); $ip = Getipaddress (); $online _num = Count_online_num ($time, $IP); echo $online _num;?>

I hope this article will help you with your PHP programming.

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