How to create a dictionary without too many references in python

This article mainly introduces how to create a dictionary without too much reference by python. it is a very practical technique, for more information about how to create a dictionary, see the example in this article. Share it with you for your reference. The specific implementation method is as follows:

1. use the itertools module

import itertoolsthe_key = ['ab','22',33]the_vale = ['aaaa',"dddddddd",'22222222222']d = dict(itertools.izip(the_key,the_vale))print d

2. Add parameters

dict = dict(red = 1,bule = 2,yellow = 3)print dict

Result: {'yellow': 3, 'bucket': 2, 'Red': 1}

3. Use Built-In zip functions
Zip ([iterable,...]) returns a list,

the_key = ['ab','22',33]the_vale = ['aaaa',"dddddddd",'22222222222']dict2 = dict(zip(the_key,the_vale))print type(zip(the_key,the_vale))print dict2

Result:

 
  {33: '22222222222', 'ab': 'aaaa', '22': 'dddddddd'}
 

4. fromkeys function of dict
Each created Key has the same value.

fromkeys(seq[,value])Create a new dictionary with keys from seq and values set to value.the_key = ['ab','22',33]the_vale = 0d = dict.fromkeys(the_key,the_vale)print 

Result: {33: 0, 'AB': 0, '22': 0}

import stringcount_by_letter = dict.fromkeys(string.ascii_lowercase,0)print count_by_letter

Result:

{'a': 0, 'c': 0, 'b': 0, 'e': 0, 'd': 0, 'g': 0, 'f': 0, 'i': 0, 'h': 0, 'k': 0, 'j': 0, 'm': 0, 'l': 0, 'o': 0, 'n': 0, 'q': 0, 'p': 0, 's': 0, 'r': 0, 'u': 0, 't': 0, 'w': 0, 'v': 0, 'y': 0, 'x': 0, 'z': 0}

I hope this article will help you learn Python programming.