How to implement a number of days after a given date (somewhat like DateAdd in VB)

How to implement a number of days after a given date (somewhat like DateAdd in VB)
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These days suddenly a lot of people ask such a question, is how to implement in PHP in VB DateAdd function, hehe! This is a question.
Originally this problem is tofu to apply to Huawei when a test question, but was implemented in C + +. Never thought of such a large company, unexpectedly
However, in this kind of pediatrics to test: Later, I did not go, these two days should http://www.chinaspx.com net friend--"luck, with PHP again
Wrote this function.
This function is very simple, is added to the specified time plus a day, get the new generated date, if you want to expand, it is also very simple.
Let's start with this function, first of all, to tell a function in advance to determine whether the current is a leap year
function Checkrun ($year) {
if ($year%4==0 && ($year%100!=0 | | | $year%400==0))
return true;
Else
return false;
}
We're going to use this function in the following program
function DateAdd ($date) {
$parts = Explode (", $date);
$date = $parts [0];
$time = $parts [1];
$ymd = Explode ('-', $date);
$hms = Explode (': ', $time);
$year = $ymd [0];
$month = $YMD [1];
$day = $ymd [2];
$hour = $hms [0];
$minute = $hms [1];
$second = $hms [2];
$day = $day +1; Say less, add a date first
if ($month = = ' 1 ' | | $month = = ' 3 ' | | $month = ' 5 ' | | | $month = ' 7 ' | | | $month = ' 8 ' | | $month = ' | | $month = ' 12 ')
if ($day ==32)
{
$day = ' 1 ';
$month + +;
}
if ($month = = ' 4 ' | | $month = ' 6 ' | | $month = = ' 9 ' | | $month = = ' 11 ')
if ($day ==31)
{
$day = ' 1 ';
$month + +;
}
if ($month = = ' 2 ')
if (Checkrun ($year))
{
Leap year February has 29 days
if ($day ==30)
{
$day = 1;
$month + +;
}
}
Else
{
Not a leap year.
if ($day ==29)
{
$day = 1;
$month + +;
}
}
if ($month ==13)
{
$month = 1;
$year + +;
}
Return $year. "-" . $month. "-" . $day;
}
Okay, here's the test.
Echo DateAdd ("1999-12-31 11:11:11");
Echo DateAdd ("2000-2-29 11:11:11");
If you want to test the addition of several days, as long as the addition of a cycle can be, I believe we are high, this function is very simple: