1. When you click a button, change the image in the image field.
Copy codeThe Code is as follows:
<Span style = "cursor: hand" onclick = "reflush (); return false;"> invisible </span>
<Script>
Function reflush ()
{
Document. getElementById (randimg). src = "/servlet/CreateValidateNum ";
}
</Script>
2. Description
"Servlet/CreateValidateNum" is a JAVA-written servlet. The servlet prints the image.
3. Problems
The image under IE6 is modified normally, but it is not refreshed under IE7 and Firefox.
4. Situation Analysis
If the new image is different from the old image address, the effect will be displayed. That is, the image changes.
But it is similar to the "Verification Code" function. The addresses of new and old images are the same.
In view of the above situation, it is suspected that the image address is the same, which causes the browser to automatically read the cache.
5. Solution
Change javascript to this:
Document. getElementById (randimg). src = "/servlet/CreateValidateNum? "+ Math. random ();
That is, each access address is different because there is a random number. Solve the problem