How to store 4 bytes of long data in a character array?

/* Prerequisite */<br/> long a = 0x12345678; <br/> char s [5] = {0 }; </P> <p>/* method 1 */<br/>/* principle: Take the address of a and forcibly convert it to char *. (The pointer occupies one byte, exactly four bytes), then unreference the value and assign it to s [I]; */<br/> for (INT I = 0; I <4; I ++) <br/>{< br/> S [I] = * (char *) & A + I ); <br/>}</P> <p>/* method 2 */<br/>/* principle: Convert the character array (4 bytes ), forcibly convert to long pointer, unreference, and assign values; */<br/> * (long) S =; </P> <p>/* method 3 */<br/>/* principle: use the library function to copy the memory; <br/> */<br/> memcpy (S, & A, 4 ); </P> <p>/* all three of them have the same effect */<br/> printf ("% x/N ", s [0], s [1], s [2], s [3]);

 

Of course, you also need to consider the size of the machine!