[Huawei Machine Test exercises]48. Armstrong number

Topic

Describe:

如果一个正整数等于其各个数字的立方和，则该数称为阿姆斯特朗数(亦称为自恋性数)，1除外，如407 = 43+03+73就是一个阿姆斯特朗数。试编程求n(n ≤ 65536)以内的所有阿姆斯特朗数。

Interface description
Prototype:

int CalcArmstrongNumber(int n);

Input parameters:

int n: n ≤ 65536

return value:

   n以内的阿姆斯特朗数的数量

Practice Stage:

Code

/* ---------------------------------------* Date: 2015-07-04* sjf0115* title: Armstrong number * Source: Huawei Machine Test Exercises--------------------- --------------------*/#include <iostream>#include "OJ.h"using namespace Std;/ * Function: For all Armstrong number prototypes within N (n≤65536): int calcarmstrongnumber (int n); input parameter: int n:n≤65536 return value: Number of Armstrong within N. */intCalcarmstrongnumber (intN) {if(N <=1){return 0; }//if    int sum, M,tmp,Count=0; for(intI=2; I <= n;++i) {sum=0; TMP = i; while(TMP) {m = tmp%Ten;sum+ = m * m * m; TMP/=Ten; }//while        if(sum= = i) {+ +Count; }//if}//if    return Count;}

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[Huawei Machine Test exercises]48. Armstrong number