if (0 = = ' abc ') Why would it pass

if (0== ' abc ')
Why would the IF (0== ' abc ') be represented as true? Principle of seeking advice

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if (0 = = intval (' abc ')) weak type, the latter will be converted to the previous type, then the comparison

You need to use 0 = = = ' abc '
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Because ' ABC ' was strongly turned into (int) ' ABC ', and 0 = = intval (' abc ').

This behavior has not been noticed AH. I wipe, PHP which is going to reverse the day.
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strings and numbers want to judge, then will take the string int value, so ABC in the sense of int is 0, so equal, you can use = = = to judge, so even with the type also judged
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This comparison is not strict. At least use = = =
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PHP Code

Var_dump ((int) ' abc '); Int (0)
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LS two bit answered. if (0== ' abc ')  equals  if (0==intval (' abc '))
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