If different images are displayed based on the data in the database

If different images are displayed based on the data in the database, three types of data are available for mobile phone users (images). in the database type field, 1, 2 are displayed, 3 (in a total of 8 states, users can only select four, that is, when they enter the database, they can only have four data records, such as 1, 2, 4, or 1, 2, 3, or 0, 0, 0 indicates that nothing is selected ). I would like to ask: how can I display different images at the control layer based on the data in the database?
I have 3 types of data
It can be selected by mobile phone users (images)
In the database type field, 1, 2, and 3 are displayed. (in a total of 8 states, a user can only select four. that is, when entering the database, only four data items can be selected, such as 1, 2, 3, 4, or 1, 3 can also be 0, 0, 0 indicates that nothing is selected ).

I want to ask:
How to extract the field from the control layer and display the corresponding image in the VIEW layer (the image is local)
The answers should be detailed!

------ Solution --------------------
Query the table directly on the controller, and then retrieve the data of the type field as a string, and convert $ c = explode () to an array.
Create a php file in the project and write a new array in it, as shown in figure
$ A = array (
1 => '/images/1.png ',
2 => '/images/2.png ',
3 => '/images/3.png ',
4 => '/images/4.png ',
5 => '/images/5.png ',
6 => '/images/6.png ',
7 => '/images/7.png ',
8 => '/images/8.png ',
);
Include references to create files
Traverse the array. when the value of $ c is equal to the K value of $ a, it is recorded to a new two-dimensional array. then, traverse the array in the view to obtain the image path.