In Java, determine whether a string is "both numeric" and "contains numbers" and "intercepts numbers" (GO)

1. http://cherryqq.iteye.com/blog/406355

   In JavaScript, there is a method isdigit () used to determine whether a string is a number, in the Java string processing method does not have such a method, it is often necessary to use, so the Internet search, sorted out two with regular expression matching method of judgment, as follows;

   Java code
   2. Determines whether a string is numeric
   4. Public Boolean isdigit (String strnum) {
   6. return Strnum.matches ("[0-9]{1,}");
   8. }
   12. Determines whether a string is numeric
   14. Public Boolean isdigit (String strnum) {
   16. Pattern pattern = Pattern.compile ("[0-9]{1,}");
   18. Matcher Matcher = Pattern.matcher ((charsequence) strnum);
   20. return matcher.matches ();
   22. }
   26. Intercept numbers
   28. public string Getnumbers (string content) {
   30. Pattern pattern = Pattern.compile ("\\d+");
   32. Matcher Matcher = pattern.matcher (content);
   34. While (Matcher.find ()) {
   36. return Matcher.group (0);
   38. }
   40. return "";
   42. }
   46. Intercept non-digital
   48. public string Splitnotnumber (string content) {
   50. Pattern pattern = Pattern.compile ("\\d+");
   52. Matcher Matcher = pattern.matcher (content);
   54. While (Matcher.find ()) {
   56. return Matcher.group (0);
   58. }
   60. return "";
   62. }
   64. Determines whether a string contains a number
       public boolean hasdigit (String content) {
       Boolean flag = false;
       Pattern p = pattern.compile (". *\\d+.*");
       Matcher m = p.matcher (content);
       if (M.matches ())
       Flag = true;
       return flag;
       }
   Three ways to judge whether a string is a number in Java
   1 functions in Java
   public static Boolean isnumeric (String str) {
   for (int i = Str.length ();--i>=0;) {
   if (! Character.isdigit (Str.charat (i))) {
   return false;
   }
   }
   return true;
   }
   
   2 Using regular expressions
   public static Boolean isnumeric (String str) {
   Pattern pattern = Pattern.compile ("[0-9]*");
   return Pattern.matcher (str). matches ();
   }
   
   3 with ASCII code
   
   public static Boolean isnumeric (String str) {
   for (int i=str.length ();--i>=0;) {
   int Chr=str.charat (i);
   if (chr<48 | | chr>57)
   return false;
   }
   return true;
   }

In Java, determine whether a string is "both numeric" and "contains numbers" and "intercepts numbers" (GO)