Initialization order of classes in Java

Test code:

1  Public classTest022 {3      PublicTest02 ()4     {5System.out.println ("Test02");6     }7      Public Static voidMain (string[] args)8     {9Test03 test03=NewTest03 ();//1Ten         //test03.f (); //2 One        //System.out.println (test03.i);//3 A     } - } -  the classTest03 - { -     Static inti = 3; -     StaticTest02 test02 =NewTest02 (); +Test01 test01 =NewTest01 (); -      +     Static A     { atSystem.out.println ("Static"); -     } -     { -System.out.println ("Nostatic"); -     } -     Static voidf () in     { -System.out.println ("F ()"); to     } +  -      PublicTest03 () the     { *System.out.println ("Test03"); $     }Panax Notoginseng}

The result of the execution of 1 is as follows: test02statictest01nostatictest03 execution 2 results as follows: TEST02STATICF () executes 3 results as follows: TEST02STATIC3    The conclusions are as follows: 1. When you create an object, you initialize the class where the object resides, in the order of static objects > static code blocks > Generic Objects > Common code blocks > Construction Method 2. When you simply invoke a static or static method of a class, only the static behavior is initialized at this point: Static object > Static code block > static variable (static method)

Initialization order of classes in Java