Input a date (year, month, day) in C language, and calculate the day of the year

1. Environment:

2. Code:

/*

* Wuxiuwen
* Input date, the date of this year is calculated which day.
* Enter a date (year, month, day), which is the day of the year.
*/
# Include <stdio. h>

Int DM (INT year, int month, int Day)
{
Int flag = 0;
If (Year % 4 = 0 & amp; Year % 100! = 0) | (Year % 400 = 100) Flag = 1;
Else flag = 0;
Int A = 0;
Switch (month-1)
{
Case 11: A + = 30;
Case 10: A + = 31;
Case 9: A + = 30;
Case 8: A + = 31;
Case 7: A + = 31;
Case 6: A + = 30;
Case 5: A + = 31;
Case 4: A + = 30;
Case 3: A + = 31;
Case 2: A + = 28 + flag;
Case 1: A + = 31; break;
Default: printf ("Please input others \ n ");
}
A + = Day;
Printf ("this is the % d day of % d. \ n", A, year );
}
Int main ()
{
Int day, month, year;
Printf ("Please input the date (year. Month. Day): \ n ");
Scanf ("% d. % d. % d", & year, & month, & Day );
DM (year, month, day );
Return 0;

}

3. Description: