Inputs a date (e.g. July 4, 2008) and outputs the day of the week-judge the day of the week based on the input date

Inputs a date (e.g. July 4, 2008) and outputs the day of the week-judge the day of the week based on the input date:

//inputs a date (e.g. July 4, 2008) and outputs the day of the week#include<iostream>#include<string>using namespace std;bool leapyear;void getInput(string& a,int& month,int& day,int& year);bool isLeapYear(int year);int getCenturyValue(int year);int getYearValue(int year);int getMonthValue(string a,int month,int year);int main(){    int month,day,year,week;    int centuryvalue,yearvalue,monthvalue;    string a,b;        getInput(a,month,day,year);    leapyear = isLeapYear(year);    cout<<"isLeapYear "<<leapyear<<endl;    centuryvalue = getCenturyValue(year);    cout<<"centuryvalue "<<centuryvalue<<endl;    yearvalue = getYearValue(year);    cout<<"yearvalue "<<yearvalue<<endl;    monthvalue = getMonthValue(a,month,year);    cout<<"monthvalue "<<monthvalue<<endl;        week = (day + monthvalue + yearvalue + centuryvalue) % 7;    cout<<"week "<<week<<endl;    switch(week)    {        case 1:            b = "Monday";            break;        case 2:            b = "Tuesday";            break;        case 3:            b = "Wednesday";            break;        case 4:            b = "Thursday";            break;        case 5:            b = "Firday";            break;        case 6:            b = "Saturday";            break;        case 0:            b = "Sunday";            break;        default:            cout<<"ERROR!";    }    cout<<"The day of week is "<<b<<endl;        return 0;}void getInput(string& a,int& month,int& day,int& year){    int number;    cout<<"Enter the date:"<<endl;    cout<<"1:month is english,"<<endl;    cout<<"2:month is numbers."<<endl;    cin>>number;    switch(number)    {        case 1:            cout<<"Enter the date(july 4 2008):\n";            cin>>a>>day>>year;            break;        case 2:            cout<<"Enter the date(7 4 2008):\n";            cin>>month>>day>>year;            break;        default:            cout<<"Error!";    }}bool isLeapYear(int year){    if(0 == year % 400 || (year % 4 ==0 && 0 != year % 100))        return 1;    return 0;}int getCenturyValue(int year){    int tem;    tem =(3 - (year / 100) % 4)*2;    return tem;}int getYearValue(int year){    int tem;    tem = (year % 100) / 4 + year % 100;    return tem;}int getMonthValue(string a,int month,int year){    if(a == "october" || month == 10 || (a == "january" && (!leapyear)) || (month == 1 && (!leapyear)))        return 0;    else if(a == "may" || month == 5)        return 1;    else if(a == "august" || month == 8 || (a == "february" && (leapyear)) || (month == 2 && (leapyear)))        return 2;    else if(a == "march" || month == 3 || a == "november" || month == 11 || (a == "february" && (!leapyear)) || (month == 2 && (!leapyear)))        return 3;    else if(a == "june" || month == 6 )        return 4;    else if(a == "september" || month == 9 || a == "december" || month == 12)        return 5;    else if(a == "april" || month == 4 || a == "july" || month == 7 || (a == "january" && (leapyear)))        return 6;    return -1;}

Result:

Enter the date:1:month is english,2:month is numbers.2Enter the date(7 4 2008):9 1 2014isLeapYear 0centuryvalue 6yearvalue 17monthvalue 5week 1The day of week is MondayEnter the date:1:month is english,2:month is numbers.2Enter the date(7 4 2008):7 4 2008isLeapYear 1centuryvalue 6yearvalue 10monthvalue 6week 5The day of week is FirdayEnter the date:1:month is english,2:month is numbers.1Enter the date(july 4 2008):july 4 2008isLeapYear 1centuryvalue 6yearvalue 10monthvalue 6week 5The day of week is Firday

Inputs a date (e.g. July 4, 2008) and outputs the day of the week-judge the day of the week based on the input date