# Interview question: produce an array of length 100, each item in the array randomly fills the number between 1-100 and guarantees no repetition

Source: Internet
Author: User
Tags repetition

Turn from: http://blog.csdn.net/yanghua_kobe/article/details/6253227

This is an interview question:

Refer to 3 ways on the Web, C # implementation:

Method One:

[C-sharp]  View plain copy print? #region   Method One                // Storage 1-100                int[] num  = new int[100];                //indexNum[0]=1;...indexNum[99]=100; (not repeat)                 for  (Int i = 0; i < num. length; i++)                {                    num[i]  = i + 1;                }               Random r  = new rAndom ();               //storage Final Results                 int[] result =  new int[100];               int  max = 100;//set the maximum value of random number                 for  (Int j = 0; j < result. length; j++)                {                    // Computes the randomly generated array index (0-99)   NOTE: The upper bound value:100  cannot be taken to                     int index = r.next (0, max);                    //Check out the number of the index stored in the location                     result[j] = num[index];       &NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;&NBSP;//replaces the number that has been put into result with the last number                     // In this way, the numbers from 0 to max-1 in the NUM array are not stored in result and are not duplicated                     num[index] = num[max - 1];                    //randomly generated array index Max minus one                     max--;                }                //Print Results                 for  (int i = 0; i < 100; i++)                 {                    if  (i % 10 == 0)                    {                         console.writeline ("/r/n");                    }                    console.write (result[i] +  " ");               }                console.read ();                 #endregion

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