Interview questions, java interview questions
1. Use case when to perform subqueries
SELECT u.id user_id, u.username user_username, g.id group_id,
CASE g.flag
WHEN '0' THEN g.groupcode
ELSE (SELECT t.fullname FROM tab_0009 t WHERE t.id = g.id)
END AS group_groupname,
CASE g.flag
WHEN '0' THEN g.groupname
ELSE (SELECT t.fullcode FROM tab_0009 t WHERE t.id = g.id)
END AS group_groupcode,
u_g.id usergroup_id, u_g.user_id usergroup_userId, u_g.group_id usergroup_groupId
FROM user_group u_g RIGHT JOIN t_group g ON u_g.group_id = g.id LEFT JOIN t_user u ON u_g.user_id = u.id
2. Externally connect t_group and tab_0009, and finally stitch the fields
SELECT u.id user_id, u.username user_username, g.id group_id,
CONCAT (IFNULL (g.groupname, ''), IFNULL (t.fullname, '')) group_groupname,
CONCAT (IFNULL (g.groupcode, ''), IFNULL (t.fullcode, '')) group_groupcode,
u_g.id usergroup_id, u_g.user_id usergroup_userId, u_g.group_id usergroup_groupId
FROM user_group u_g, t_user u, t_group g LEFT JOIN tab_0009 t ON t.id = g.id WHERE u_g.group_id = g.id AND u_g.user_id = u.id;
FROM user_group u_g RIGHT JOIN t_group g ON u_g.group_id = g.id LEFT JOIN t_user u ON u_g.user_id = u.id,
t_group g1 LEFT JOIN tab_0009 t ON t.id = g1.id WHERE g1.id = g.id;
SELECT u.id user_id, u.username user_username, g.id group_id,
g.groupname group_groupname,
g.groupcode group_groupcode,
u_g.id usergroup_id, u_g.user_id usergroup_userId, u_g.group_id usergroup_groupId
FROM user_group u_g RIGHT JOIN t_group g ON u_g.group_id = g.id LEFT JOIN t_user u ON u_g.user_id = u.id
WHERE g.flag! = 0
UNION
SELECT u.id user_id, u.username user_username, g.id group_id,
(SELECT t.fullname FROM tab_0009 t WHERE t.id = g.id) group_groupname,
(SELECT t.fullcode FROM tab_0009 t WHERE t.id = g.id) group_groupcode,
u_g.id usergroup_id, u_g.user_id usergroup_userId, u_g.group_id usergroup_groupId
FROM user_group u_g RIGHT JOIN t_group g ON u_g.group_id = g.id LEFT JOIN t_user u ON u_g.user_id = u.id
WHERE g.flag = 0
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