Introduction to how to replace multiple characters in Python

the conclusion is given first:
The number of characters to be replaced can be directly linked

Replace ()

method to replace, the efficiency is very high;
If the number of characters to replace is large, it is recommended to call in the For loop

Replace ()

be replaced.
Possible methods:
1. Chained replace ()

String.Replace (). Replace ()

1.x in

For

Calling in Loops

Replace ()

"When there are more characters to replace"
2. Using String.maketrans
3. Re.compile First and then Re.sub
......

def A (text): chars = "" for C in chars:text = Text.replace (c, "\ \" + c) def b (text):  For ch in [' & ', ' # ']: if ch in text:text = Text.replace (ch, "\ \" +ch) import redef C (text): Rx = Re.compile (' ([[]) ') text = Rx.sub (R ' \\\1 ', text) Rx = Re.compile (' ([[]) ') def d (text): Text = rx.sub (R ' \\\1 ', text) def mk_esc (esc_chars): Return lamb Da s: '. Join ([' \ \ \ ' + c if C in Esc_chars else C for C in S]) ESC = Mk_esc (') def e (text): ESC (text) def f (text): Text = Tex T.replace (' & ', ' \& '). Replace (' # ', ' \# ') def g (text): replacements = {"&": "\&", "#": "\#"} Text = "". Join ([ Replacements.get (c, c) for C in text]) def h (text): Text = Text.replace (' & ', R ' \& ') Text = Text.replace (' # ', R ' \# ') def i (text): Text = Text.replace (' & ', R ' \& '). Replace (' # ', R ' \# ')