This article mainly introduces how to use an instance to explain the problem of DB2 cursor loop. If you are curious about using an instance to explain the problem of DB2 cursor loop, the following articles will unveil its secrets. The following is a detailed description of the article. I hope you can learn from it.
The stored procedure example in this article shows that the expected number of cycles is the number of rows in the yh table. Because select iid into pint from yh where 0 = 1; No rows are returned, so after at_end, it will immediately be equal to 1 (only one loop will exit ).
- DECLARE at_end INT DEFAULT 0;
- DECLARE PIID INTEGER DEFAULT 0 ;
- DECLARE PINT INTEGER DEFAULT 0 ;
- DECLARE not_found CONDITION FOR SQLSTATE '02000';
- --DECLARE PCOUNT INTEGER;
- DECLARE c1 CURSOR FOR
- SELECT IID FROM YH;
- DECLARE CONTINUE HANDLER FOR not_found
- SET at_end = 1;
- OPEN c1;
- SET PCOUNT=0;
- ins_loop:
- LOOP
- FETCH c1 INTO PIID;
- IF at_end <>0THEN
- LEAVE ins_loop;
- END IF;
- SET PCOUNTPCOUNT=PCOUNT+1;
- SELECT IID INTO PINT FROM YH WHERE 0=1;
- END LOOP;
The above content is an introduction to the problem of DB2 cursor loop with an instance. I hope you will gain some benefits.
The above content describes how to use an instance to explain the problem of DB2 cursor loop. I hope it will help you in this regard.