IOS calls and returns to the application

When we call this function, we often call this method:

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"tel://xxxxx"]];

However, after the function is implemented, you cannot return to your application after the call is completed. I recently searched a lot on the Internet, and Apple did not provide callback functions. Powerful netizens use the uiwebview control to implement this method.

The Code is as follows:

- (void) dialPhoneNumber:(NSString *)aPhoneNumber  {      NSURL *phoneURL = [NSURL URLWithString:[NSString stringWithFormat:@"tel:%@",aPhoneNumber]];      if ( !phoneCallWebView ) {                  phoneCallWebView = [[UIWebView alloc] initWithFrame:CGRectZero];      }      [phoneCallWebView loadRequest:[NSURLRequest requestWithURL:phoneURL]];  }  - (void) dealloc  {      // cleanup      [phoneCallWebView release], phoneCallWebView = nil;     [super dealloc];  }  

There is also a method that cannot be uploaded to the appstore.

[[UIApplication sharedApplication] openURL:[NSURL URLWithString:@"telprompt://xxxx"]];  

That is, change Tel to telprompt.

You can try it.