IOS QQ Third party login Implementation _ios

This example for you to share the iOS QQ Third-party login Implementation code for your reference, the specific contents are as follows

First, preparatory work

1, to QQ open platform (http://connect.qq.com/) registered as a developer, apply for Appkey,
2, in the URL types add QQ AppID, its format is: "Tencent" + AppID such as tencent1104463316

Second, configure APPDELEGATE.M

1, import <TencentOpenAPI/QQApiInterface.h> and <TencentOpenAPI/TencentOAuth.h> two header files
2. Configuration function:

-(BOOL) Application: (UIApplication *) application Handleopenurl: (nsurl *) URL 
{return 
  [Tencentoauth Handleopenurl:url]; 
} 
 
-(BOOL) Application: (UIApplication *) application OpenURL: (nsurl *) URL sourceapplication: (NSString *) sourceapplication annotation: (id) annotation 
{return 
  [Tencentoauth Handleopenurl:url]; 

Set up code in the login interface

1, import #import <TencentOpenAPI/TencentOAuth.h>
2, comply with the agreement:<tencentsessiondelegate>
3, trigger the login method to write code:

-(void) Qqlogin 
{ 
  nsarray* permissions = [Nsarray arraywithobjects: 
              kopen_permission_get_user_info, 
              Kopen_permission_get_simple_user_info, 
              kopen_permission_add_album, 
              nil Nil]; 
  [Self.tencentoauth authorize:permissions]; 
} 

4, get the user information

-(void) Tencentdidlogin 
{ 
  [Self.tencentoauth getuserinfo]; 
} 
[OBJC] View plain copy on code that is derived from my Code slice
-(void) Getuserinforesponse: (apiresponse*) response 
{ 
  NSLog (@ "GetUserInfo =%@", response.jsonresponse); 
  NSLog (@ "getuserinfo.nickname =%@", [response.jsonresponseobjectforkey:@ "nickname"]); 
  nsstring* alertmessage = [nsstringstringwithformat:@ "%@", Response.jsonresponse]; 
  nsstring* Headerpath = [response.jsonresponseobjectforkey:@ "figureurl_qq_2"]; 
  nsstring* name = [response.jsonresponseobjectforkey:@ "nickname"]; 

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