Java access to keyboard input method

Import Java.io.BufferedReader;   Import java.io.IOException;   Import Java.io.InputStreamReader;   Import Java.util.Scanner;      public class MainClass   {      public static void Method1 ()    &N Bsp  {          //Use Scanner           scanner scanner=new S Canner (system.in);           system.out.print ("Please input a number:");           int num=scanner.nextint ();  //Get integer value            //string temp = Scanner.next ();//Get String value           SYSTEM.OUT.PRINTLN ("The number you are:" +num);           system.out.println ("----------------------------");           system.out.print ("Please input some character:");           string Str=scanner.Next ();  //Get String value           SYSTEM.OUT.PRINTLN ("The string you are:" +STR);                 &nbsp}       public static void Method2 ( )       {          //using BufferedReader        &NBSP ;  try           {              bufferedreader R Eader=new BufferedReader (New InputStreamReader (system.in));               system.out.print ("Please input a number:");               string str=reader.readline ();  //get string               SYSTEM.OUT.PRINTLN ("The number you are:" +STR);          &nbsp} catch (IOException e)           {   &NB Sp         &Nbsp;e.printstacktrace ();           }       }  
public static void Method3 () {//define byte array length, and do exception handling, read current bytes byte[] buffer= new Byte[len];        try {System.in.read (buffer, 0, Len);                 catch (Exception e) {} String str = newstring (buffer);          System.out.println (str); } }
PostScript: The second method uses the ReadLine () method to return a value of type string. If you want to get an int or float type, you need a write-type conversion function on the row conversion