JAVA amounts are apportioned proportionally, with zero Header Processing and java amounts allocated with zero Header

Source: Internet
Author: User

JAVA amounts are apportioned proportionally, with zero Header Processing and java amounts allocated with zero Header

  • Exact amount calculation is requiredBigDecimal;
  • Evenly distributed, with a fraction of the allocation, usually composed of "precision" andApportionment CoefficientDetermined;
  • HowZero HeaderTo ensureAverage as much as possibleAllocate.

1. Shared by households

/*** Assignment by number of households ** objective: to allocate a specified amount of RMB 200 to six households on average, with the same amount before and after the assignment */private static void hsFt () {BigDecimal [] repair_shou_Amt = new BigDecimal [6]; // The service amount BigDecimal fact_repair_Amt = new BigDecimal ("0") for each sub-account; // The actual fee (excluding the null value) // The amount to be apportioned: BigDecimal ft_amt = new BigDecimal ("200"); // the total number of households: int count = repair_shou_Amt.length; for (int I = 0; I <count; I ++) {// calculate the undertaking amount of each sub-account = apportioned amount/total number of accountsRepair_shou_Amt [I] = ft_amt.divide (new BigDecimal (count), 2, BigDecimal. ROUND_DOWN );// Actual total apportioned amount --- total amount after decimal point truncation fact_repair_Amt = fact_repair_Amt.add (repair_shou_Amt [I]);} // fraction = apportioned actual undertaking amount-amount to be apportioned BigDecimal repair_oddment_amt = fact_repair_Amt.subtract (ft_amt); // calculates the number of accounts to be apportioned to the fraction (accuracy: 0.01, so * 100)Int repair_int = repair_oddment_amt.multiply (new BigDecimal ("100"). abs (). intValue ();// Distribute the repair amount to the sub-accounts. if the number of sub-accounts involved in the repair is greater than zero or less than the total number, allocate if (repair_int <count) & (repair_int> 0) {// If the fraction is smaller than zero, it indicates that the amount of the repair_int sub-households is less than 0.01 RMB, add a penny if (repair_oddment_amt.compareTo (new BigDecimal ("0") <0) {for (int I = 0; I <repair_int; I ++) {repair_shou_Amt [I] = repair_shou_Amt [I]. add (new BigDecimal ("0.01") ;}} else {// If the zero header is greater than zero, it indicates that the amount of one sub-account with a repair_int is 0.01 more than one cent, you need to deduct a penny for (int I = 0; I <repair_int; I ++) {r Epair_shou_Amt [I] = repair_shou_Amt [I]. subtract (new BigDecimal ("0.01") ;}} else if (repair_int = 0) {// if the zero header is zero, indicates the amount has been evenly distributed} else {throw new BusinessException ("invalid operation! ");}}

2. Evenly distributed by area

/*** Area-based allocation method * objective: to allocate a specified amount of RMB 200 to six households on average. The area of each household may vary, and the amount before and after the allocation is equal */public static void areaFt () {BigDecimal [] repair_shou_Amt = new BigDecimal [6]; // The service amount BigDecimal fact_repair_Amt = new BigDecimal ("0 "); // actual cost of the service object (excluding the first item) // The amount to be apportioned BigDecimal ft_amt = new BigDecimal ("200"); // the total number of households int count = repair_shou_Amt.length; // The household area is BigDecimal [] info_area = {new BigDecimal ("20.12"), new BigDecimal ("10.12"), new BigDecimal ("11.12 "), new BigDecimal ("15.12"), new BigDecimal ("10.12"), new BigDecimal ("110.12")}; // The allocated total area BigDecimal totalArea = ObjectUtil. getZeroBigDecimal (); for (int I = 0; I <count; I ++) {totalArea = totalArea. add (info_area [I]) ;}for (int I = 0; I <count; I ++) {BigDecimal oa_hou_area = info_area [I]; // calculate the undertaking amount for each sub-household = (sub-household area/total construction area) * apportioned amountRepair_shou_Amt [I] = (oa_hou_area.multiply (ft_amt). divide (totalArea, 2, BigDecimal. ROUND_DOWN ));// Actual total apportioned amount --- total amount after decimal point truncation fact_repair_Amt = fact_repair_Amt.add (repair_shou_Amt [I]);} // fraction = apportioned actual undertaking amount-amount to be apportioned BigDecimal repair_oddment_amt = fact_repair_Amt.subtract (ft_amt); // calculates the number of accounts to be apportioned to the fractionInt repair_int = repair_oddment_amt.multiply (new BigDecimal ("100"). abs (). intValue ();// Distribute the repair amount to the sub-accounts. if the number of sub-accounts involved in the repair is greater than zero or less than the total number, the sub-accounts will be apportioned. Otherwise, if (repair_int <count) is reported) & (repair_int> 0) {// If the fraction is smaller than zero, it indicates that the amount of the repair_int sub-households is less than 0.01 RMB, add a penny if (repair_oddment_amt.compareTo (new BigDecimal ("0") <0) {for (int I = 0; I <repair_int; I ++) {repair_shou_Amt [I] = repair_shou_Amt [I]. add (new BigDecimal ("0.01") ;}} else {// If the zero header is greater than zero, it indicates that the amount of one sub-account with a repair_int is 0.01 more than one cent, you need to deduct a penny for (int I = 0; I <repair_int; I + +) {Repair_shou_Amt [I] = repair_shou_Amt [I]. subtract (new BigDecimal ("0.01") ;}} else if (repair_int = 0) {// if the zero header is zero, no need to handle} else {throw new BusinessException ("invalid operation! ");}}

 

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