Java determines whether a birthday string is legal

Source: Internet
Author: User

Wrote a method to determine whether a user entered a birthday string, provided the input string format is YYYYMMDD.

   public static Boolean checkbirthday (String birthday) {if (Common.empty (birthday)) {return false;        } if (Birthday.length ()! = 8) {return false; The pattern pattern = pattern. Compile ("^[1,2]\\d{3} (0[1-9]| | 1[0-2]) (0[1-9]| | [Up] [0-9]| |        3[0,1]);        Matcher Matcher = Pattern.matcher (birthday);        if (!matcher.matches ()) {return false;        } Date birth = null;        try {birth = new SimpleDateFormat ("YyyyMMdd"). Parse (birthday);        } catch (ParseException e) {e.printstacktrace ();        } if (!new SimpleDateFormat ("YyyyMMdd"). Format (birth). Equals (Birthday)) {return false;        }//Gets the number of milliseconds for the current date long currenttime = System.currenttimemillis ();        Gets the number of milliseconds for a birthday long birthtime = Birth.gettime (); If the current time is less than the birthday, the birthday is not valid.        Conversely legal if (Birthtime > CurrentTime) {return false;   } return true; } 


Original address: http://www.iyuze.cn/article/609.html

Java determines whether a birthday string is legal

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