Java finds all strings that match a regular substring in a string __java

The code is as follows:

String line = "October 11, 2016 Where do we go to play recently we recently, the following year, the same years, October, 2019, March 4" pattern
Datepattern = Pattern.compile ("\\d{4} year \\d {1,2} month \\d{1,2} Day |\\d{4} year \\d{1,2} |\\d{1,2} month \\d{1,2} Day |\\d{4} |\\d{1,2} month | The same year | The following week | recently | recently ");
Matcher datematcher = Datepattern.matcher (line);
int datecount = 0;
while (Datematcher.find ()) {
    System.out.println (Datematcher.group ());
    ++datecount;
}

As the code above is lookup, all the matches in the string are: month, month, year, months, months, years, year, day, recent, recently, substring

This involves greedy matching or not greedy match, as if with the regular order, as above, I will long match in front, namely first month, month, day, year, month and so on. I put the regular in this order, so I can achieve greedy matching.

Furthermore

If you have the following string

String line = "[[444444444444],[5555555555555]]";

I'm going to take the string out of each [] individually, and I can use the following regular

Pattern Categorypattern = Pattern.compile ("\\[\". *?\ "\]"); When you add a question mark, it's a greedy match.

Note: If none of the above. The number is greedy regular, this will only match to the outermost, that will only match to one, but add a question mark to become not greedy, you can achieve the right match