JAVA long integer to IP address method, java integer

JAVA long integer to IP address method, java integer

How to convert a JAVA long integer to an IP address

The Code is as follows:

/*** Resolve an integer to an IP address * @ param num * @ return */public static String int2iP (Long num) {String str = null; long [] tt = new Long [4]; tt [0] = (num >>> 24) >>> 0; tt [1] = (num <8)> 24)> 0; tt [2] = (num <16)> 24; tt [3] = (num <24) >>> 24; str = (tt [0]) + ". "+ (tt [1]) + ". "+ (tt [2]) + ". "+ (tt [3]); return str ;}

In java, how does one convert the Double Precision type to a long integer?

Directly force conversion to drop ~~~ Just add a long value before the double-precision value ~~

Integer Conversion to string in JAVA

1. Because you use the parse () method, you can only convert string type to numeric type .!
You cannot convert an integer to a string ,! Otherwise, an error occurred while compiling .!

2. Convert () conversion is recommended,
It can switch between various basic data types ,!

Conversion of various basic data types is as follows:

Convert. Tolnt32 () converts an integer
Convert. Tosingle () to single-precision floating point
Convert. ToDouble () to double-precision floating point
Convert. ToString () to string type