Java date format verification several instance programs

Source: Internet
Author: User
Tags java format

This article will introduce you to a date format verification example. This is a date verification program written by another student. I hope this method will be helpful to you.

Requirement: because the system has many date formats, the input of the date verification function is a date string and a format string. The format string is defined in Java format (reference address ).
At the beginning, I thought it was very simple. I wrote the following code directly.

The Code is as follows: Copy code

Public static boolean isDate (String dttm, String format ){
Boolean retValue = false;
If (dttm! = Null ){
SimpleDateFormat formatter = new SimpleDateFormat (format );
Try {
Formatter. parse (dttm );
RetValue = true;
} Catch (ParseException e ){
}
}
Return retValue;
}

After writing it, I tested it and found that the date 2012/12/43 also returned True, so I checked the data and set the conversion without carrying formatter. setLenient (false); then I used it, and the code is

The Code is as follows: Copy code

Public static boolean isDate (String dttm, String format ){
Boolean retValue = false;
If (dttm! = Null ){
SimpleDateFormat formatter = new SimpleDateFormat (format );
Formatter. setLenient (false );
Try {
Formatter. parse (dttm );
RetValue = true;
} Catch (ParseException e ){
}
}
Return retValue;
}

Here, I thought everything would be fine. However, tests later showed that only the first part of the date will be converted when there is a separator. For example, 2012/12/43ABCD will return True. After thinking about it, I thought it would be converted to the date type, then to the string type, and then compare whether the two are equal, but I immediately rejected this scheme because the customer requested a non-strict date format, for example, if the format is yyyy/MM/dd, enter 2012/1/2 to pass the verification. Then I thought about it. I thought we should first use a regular expression for verification and then verify whether it is a date type. The Code is as follows:

The Code is as follows: Copy code

Public static boolean isDate (String dttm, String format ){
Boolean retValue = false;

If (dttm = null | dttm. isEmpty () | format = null | format. isEmpty ()){
Return retValue;
}

String regFormat = format;
RegFormat = regFormat. replaceAll ("(^ ') | (' $ )","");
RegFormat = regFormat. replaceAll ("'([^'])", "$1 ");
RegFormat = regFormat. replace ("''","'");
RegFormat = regFormat. replace ("\","\\");
RegFormat = regFormat. replaceAll ("[MdHmsS] +", "\ d + ");
RegFormat = regFormat. replaceAll ("[y] +", "\ d {1, 4 }");
If (! Dttm. matches ("^" + regFormat + "$ ")){
Return false;
}

SimpleDateFormat formatter = new SimpleDateFormat (format );
Formatter. setLenient (false );
Try {
Formatter. parse (dttm );
RetValue = true;
} Catch (ParseException e ){
}

Return retValue;
}

The above Code only corresponds to yMdHmsS. Although it is enough for the system at that time, it still does not feel very good. I think there should be a general method. Check the Java API and find that the parse method also has a parameter method. After understanding how to use it, change the code to the following:

The Code is as follows: Copy code

Private static boolean isDate (String dttm, String format ){
If (dttm = null | dttm. isEmpty () | format = null | format. isEmpty ()){
Return false;
}

DateFormat formatter = new SimpleDateFormat (format );
Formatter. setLenient (false );
ParsePosition pos = new ParsePosition (0 );
Date date = formatter. parse (dttm, pos );

If (date = null | pos. getErrorIndex ()> 0 ){
Return false;
}

If (pos. getIndex ()! = Dttm. length ()){
Return false;
}

Return true;
}

I thought it would be fine, but two bugs were found in subsequent tests. One is that when the input date does not have a year (the year is not input by default), the default value is 1970. In this case, if the year is a leap year, the verification fails on the 9th. The other is that the date size of Java is different from that of Oracle. Oracle seems to support up to 2/29, while Java can support more than 20 thousand years. So the code is changed to the following:

The Code is as follows: Copy code

Private static boolean isDate (String dttm, String format ){
If (dttm = null | dttm. isEmpty () | format = null | format. isEmpty ()){
Return false;
}

If (format. replaceAll ("'. +? '"," "). IndexOf (" y ") <0 ){
Format + = "/yyyy ";
DateFormat formatter = new SimpleDateFormat ("/yyyy ");
Dttm + = formatter. format (new Date ());
}

DateFormat formatter = new SimpleDateFormat (format );
Formatter. setLenient (false );
ParsePosition pos = new ParsePosition (0 );
Date date = formatter. parse (dttm, pos );

If (date = null | pos. getErrorIndex ()> 0 ){
Return false;
}
If (pos. getIndex ()! = Dttm. length ()){
Return false;
}

If (formatter. getCalendar (). get (Calendar. YEAR)> 9999 ){
Return false;
}

Return true;
}

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