Java String pattern function replaces all whitespace characters

The following features are given in the Java Java.util.regex.Pattern class:

Predefined character classes
.	Any character (may or may not match the line terminator)
/d	Number: [0-9]
/d	Non-digit: [^0-9]
/s	whitespace characters: [/t/n/x0b/f/r]
/S	Non-whitespace characters: [^/s]
/w	Word characters: [a-za-z_0-9]
/w	Non-word characters: [^/w]

Greedy quantity Word
X?	X, not once or once
x*	X, 0 or more times
x+	X, one or more times
X{n}	X, exactly n times
X{n,}	X, at least n times
X{N,M}	X, at least n times, but not more than m times

The function of the following example replaces all whitespace characters in a string with/T, and then split

public class Spacereplace {

/**
* @param args
*/
public static void Main (string[] args) {
TODO auto-generated Method Stub

String s = "1 3 2 4 we dads Daj";
System.out.println (s);
S=s.replaceall ("//s+", "T");
String [] sa = S.split ("/t");
System.out.println (s);
}

}